5x^2=40x-80

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Solution for 5x^2=40x-80 equation: 



5x^2=40x-80

We move all terms to the left:

5x^2-(40x-80)=0

We get rid of parentheses

5x^2-40x+80=0

a = 5; b = -40; c = +80;
Δ = b2-4ac
Δ = -402-4·5·80
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{40}{10}=4$

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